Circle
Exam focusCircle equations, chords, and tangents under Advanced ask types.
Syllabus points
- Circle: forms, tangent/normal/chord, parametric; intersections
Math notesCoordinateCircle
Independent topic page
Circle full marks: complete square → centre/radius → one tool (tangent length, chord of contact, S₁−S₂) → verify with a point.
01. General x²+y²+2gx+2fy+c=0 → centre (−g,−f), r=√(g²+f²−c). Completing square prevents g,f sign errors.
02. Length of tangent from (x₁,y₁) is √S₁ (when outside). Chord of contact from external point is T=0.
03. Two circles: S₁−S₂=0 is radical axis / common chord line when they intersect.
04. Condition that y=mx+c touches x²+y²=r²: c²=r²(1+m²) (standard); generalise carefully after shift.
05. Advanced lane: general equation → complete the square before centre/radius tools. Wrong centre poisons every later chord/tangent formula.
06. Two circles: S₁−S₂ gives the common chord line; power/length tools beat solving simultaneous quadratics when the ask is chord or length.
Official · 2026
Official syllabus points for Circle only — not the full Coordinate portion map. Portion hub: Coordinate · Coordinate Geometry analysis.
No topic-specific exclusions flagged — finish the unit points below for Circle.
Source: https://jeeadv.ac.in/documents/jee-advanced-2026-syllabus.pdf
Exam focusCircle equations, chords, and tangents under Advanced ask types.
Syllabus points
2020–2026 paper weight
Topic match inside parent portion Coordinate Geometry (12.8% of Math tags). Stats below are portion backdrop; matched subtopics show where Circle sits.
Portion-wide type/difficulty mix lives on the Coordinate Geometry analysis — not repeated here so this page stays on Circle.
01. Dominant subtopics: Parabola (8), Circle (8), Straight line (5), Ellipse (5).
Full PCM trends board → · Coordinate Geometry subject page →
Cross-topic stems
Advanced rarely asks a chapter in isolation. These are tagged multi-idea Math stems that touch Circle — practise the knowledge bridge, not only the single-chapter drill.
Step 1: recover points P, Q, R from the slope/tangent conditions on the parabola. Step 2: find the circumcircle of triangle PQR (perpendicular bisectors). Step 3: read the required radius / relation that also ties to an ellipse option.
Geometry hops across three curve types in one SC item.
Practise ‘points on parabola → circle through them → conic check’ as a single drill.
Step 1: for each List-I geometric condition, reduce to a standard conic equation or point. Step 2: match coordinates/parameters in List-II without mixing ellipse and hyperbola templates. Step 3: verify one substituted point per match to avoid swap errors.
Matching lists punish template mix-ups under time pressure.
Keep a one-page conics identity sheet and practise full matching sets weekly.
Why methods matter
Circle is standardise-then-tool. These methods stop g,f sign errors and force S₁−S₂ for two-circle stems — the usual time sinks.
Removes the #1 radius/centre error before any tool is applied.
Do thisNever apply focus-style conic memory on a general circle without centre/r.
Removes the #1 radius error.
x²+y²−4x+6y−3=0 → (x−2)²+(y+3)²=16 → r=4.
Two-circle chords become a line + Pythagoras — not a quadratic jungle.
Do thisFor intersection problems, subtract equations early.
Linear common chord without solving quadratics fully.
Then drop perpendicular from centre to get chord length.
Stops illegal √S₁ from interior points.
Do thisEvaluate S₁ sign before tangent-length formula.
Prevents illegal √ of negative.
S₁>0 outside, =0 on, <0 inside (for S=0 normalised form).
Chord of contact errors are mostly T miswrites — this fixes the habit.
Do thisWrite T correctly for the given circle form.
Chord of contact errors are mostly T miswrites.
For x²+y²=r², T is xx₁+yy₁=r².
Processed examples
Read the impact line first. Then notice which family/model was chosen. The solution is written the way your rough sheet should look in the hall.
Length of tangent from (4,0) to x²+y²=4.
√S₁ is instant once you know the point is outside.
Model chosenS₁ at (4,0) → √S₁.
Answer2√3
Takeaway: Check S₁ sign before taking square root.
Find centre and radius of x²+y²−4x+6y−3=0.
Completing square (or reading g,f,c) is the gate for every later tool.
Model chosenComplete square / centre (−g,−f).
AnswerCentre (2,−3), r=4
Takeaway: Standardise before any formula sheet.
Find the length of the common chord of x² + y² − 4x − 5 = 0 and x² + y² − 4y − 5 = 0.
S₁ − S₂ gives the chord without solving two quadratics — that is the scoring move.
Model chosenRadical axis → centre-to-chord distance → half-chord.
Answer2√7
Takeaway: Common chord ⇒ subtract circles first; never chase both intersections.
Reusable models
Advanced stems cluster. Name the family in 10–15s, write the fast model, then run the same path. Do not invent a new plan each time.
Looks likeGeneral circle; tangent length / power / centre
Fast modelCentre (−g,−f), r → then √S₁ or T=0.
Standardisation unlocks every dictionary formula.
Do not apply √S₁ before knowing the circle form.
Looks likeTwo circles; common chord or length
Fast modelS₁−S₂=0 immediately; then perpendicular from centre + Pythagoras.
Avoids solving the full quadratic system.
Do not expand both circles fully entry-wise first.
Looks likeCondition that a line touches the circle; find c or m
Fast modelDistance from centre to line = r (or standard c²=r²(1+m²) after shift).
One geometric condition replaces substitution into quadratic discriminant.
Do not always solve intersection quadratic if distance=r is enough.
Looks likeOrthogonal circles; power of a point; angle between circles
Fast model2g₁g₂+2f₁f₂=c₁+c₂ for orthogonal; power = S₁ at the point.
Named conditions kill options without intersection algebra.
Do not find both intersection points to test orthogonality.
Hall timing
Write centre and r on rough sheet before tools.
If two circles, prefer radical axis before expanding both fully.
For common chord length: perpendicular from centre to chord + Pythagoras.
S₁<0 inside — tangent length not real; don’t force √S₁.
After the model is locked
(x−h)²+(y−k)²=r²; x²+y²+2gx+2fy+c=0 → centre (−g,−f), r=√(g²+f²−c)
Always start here
√S₁ from (x₁,y₁)
External point
T=0 from (x₁,y₁)
Pair of tangents’ chord
S₁−S₂=0
Common chord / radical axis
(h+r cosθ, k+r sinθ)
Point on circle
c²=r²(1+m²) for y=mx+c
Slope form tangents to centred circle
PA·PB = power = |S₁| ideas
Intersecting chord theorems in coordinate form
Make it automatic