Vector Algebra (Basics)
PromiseBasics full marks come from components + magnitude + unit vector + linear combination discipline — before any product is touched.
01. Why Basics is its own page: students jump to cross products with weak component hygiene and lose signs. Advanced 3D is mostly careful vector arithmetic.
02. Position vector OP = r; displacement AB = b − a. Always write free vectors as differences of position vectors when points are given.
03. Linear dependence: a, b dependent ⇔ one is scalar multiple of the other ⇔ a×b=0 (preview). Three vectors later use STP.
How Advanced asks this
- Find magnitude / unit vector
- Section formula / midpoint / collinear points
- Express a vector as linear combination of others
- Addition / scalar multiplication identities MC
- Setup step before a Dot/Cross or 3D ask
Traps that leak marks
- Using a+b as joining vector
- Swapping m,n in section formula
- Forgetting |â|=1 check
- Mixing position and free vectors
- Joining vector written as a+b
- Swapping m and n in section formula
- Skipping |â|=1 verification
Must cover (this topic)
- Addition of vectors; scalar multiplication
60–90s process
- 0–15s — Name ask: magnitude / unit / section / linear combo / collinear. Write given vectors in components.
- 15–35s — Apply the matching tool: |a|, â=a/|a|, section formula, or equate components for linear combo.
- 35–75s — Solve component equations carefully; keep fractions exact.
- 75–90s — Check |â|=1; midpoint recovers; collinear λ consistent.
Methods that change the score
Basics are component hygiene. These methods lock AB=b−a and section m:n before any product chapter begins.
Method 01 · Components first
Stops abstract symbol chaos — every later product inherits clean components.
Do this: Write every vector as ⟨x,y,z⟩ or xi+yj+zk before algebra.
Method 02 · Displacement from points
Kills the yearly a+b joining-vector trap before it starts.
Do this: Always form AB = b−a when the stem gives coordinates.
Method 03 · Section formula lock
m,n order errors disappear when you write the ratio first.
Do this: Internal m:n → (n a + m b)/(m+n) — write m,n on rough sheet.
Method 04 · Equate components for combos
Linear combination stops being guesswork.
Do this: To write a in terms of b,c, solve the 2–3 component equations.
Quick formulas
- Magnitude: |a| = √(a₁²+a₂²+a₃²) — Length of a vector
- Unit vector: â = a/|a| (a≠0) — Direction only
- Displacement: AB = b − a — Vector joining points A→B
- Section (internal): Point dividing AB in m:n is (n a + m b)/(m+n) — Internal division
- Midpoint: (a+b)/2 — m=n=1
- Collinear points: AB = λ AC (or AB×AC=0) — Three points collinear
- Linear combination: Equate components: a = x b + y c — Express in a basis of two non-parallel vectors
Common question families
Magnitude / unit / displacement
Looks like: Unit vector along AB; |a|; vector joining points
Fast model: Form AB=b−a → |AB| → â=AB/|AB|.
Section / midpoint
Looks like: Point dividing a join in m:n
Fast model: Internal: (na+mb)/(m+n); write m,n first.
Linear combination
Looks like: Express a vector in terms of two others
Fast model: Equate i,j,k components → solve for coefficients.
Collinear / coplanar points via vectors
Looks like: Show points collinear; find λ so A,B,C collinear
Fast model: AB = k AC (or area |AB×AC|=0) for collinearity in plane/space.
Sample preview · Unit vector / displacement
Find the unit vector from A(1,2,3) to B(4,0,1).
Answer: ⟨3,−2,−2⟩/√17
Displacement then magnitude then divide.