Differential equations
Exam focusSeparable, homogeneous, and linear first-order DEs as Advanced asks them.
Syllabus points
- Formation of ODEs; homogeneous first-order; separation of variables; linear first-order DE
Independent topic page
DE full marks: rewrite standard form → stamp SEP / HOM / LIN → apply only that recipe → use IC → optionally differentiate to verify.
01. Separable: dy/g(y)=f(x)dx. Homogeneous: dy/dx=f(y/x) → y=vx. Linear: dy/dx+P(x)y=Q(x) → IF=e^{∫P dx}.
02. Formation of DE / order-degree ideas appear; keep order = highest derivative order, degree = power of that derivative after clearing radicals.
03. After solving, a 10s differentiate-and-plug check catches algebra slips when time allows.
04. Keep ln|·| unless domain guarantees sign.
05. Advanced lane: classify in 15s — separable / homogeneous / linear / exact-looking. Misclassification is the mark killer; the solving template only works after the stamp.
06. Linear first-order: IF = e^{∫P dx}; multiply through and recognise d/dx[y·IF]. Initial conditions apply only after the general solution is clean.
Official · 2026
Official syllabus points for Differential Equations only — not the full Calculus portion map. Portion hub: Calculus · Calculus analysis.
No topic-specific exclusions flagged — finish the unit points below for DE.
Source: https://jeeadv.ac.in/documents/jee-advanced-2026-syllabus.pdf
Exam focusSeparable, homogeneous, and linear first-order DEs as Advanced asks them.
Syllabus points
2020–2026 paper weight
Topic match inside parent portion Calculus (28.5% of Math tags). Stats below are portion backdrop; matched subtopics show where Differential Equations sits.
Portion-wide type/difficulty mix lives on the Calculus analysis — not repeated here so this page stays on DE.
Cross-topic stems
Advanced rarely asks a chapter in isolation. These are tagged multi-idea Math stems that touch Differential Equations — practise the knowledge bridge, not only the single-chapter drill.
Step 1: set y = e^{-x} equal to y = e^{-x}(sin x + cos x) and cancel the common exponential to get a trig equation for intersection abscissae α_i. Step 2: order those roots and set up the definite integral of the difference of the two curves between α_1 and α_4 for the enclosed area β. Step 3: simplify the given log expression in β to a clean numerical value.
The stem hides trig solving inside an exponential envelope; students often integrate before finding exact limits.
Drill ‘cancel common positive factor → trig roots → area integral’ as one reflex chain.
Step 1: solve x y' = y − x³ (homogeneous/linear in y/x) to get the family y = Cx − x³/2. Step 2: impose the given condition to fix C, then use y' = 0 to locate the local max. Step 3: compare monotonicity on (1,2) and count positive roots of f = g.
Multi-correct options test DE, calculus and graph reading together; one sign error in the DE kills several options.
After every DE, immediately ask: extrema? monotonicity? intersections with a given g?
Step 1: analyse the given limit expression to identify the correct f(x) / derivative behaviour. Step 2: on a related (or following) stem, sketch the region defined by inequalities. Step 3: integrate carefully (logs appear from 1/x-type boundaries).
Back-to-back calculus depth: analytic limit then geometric area.
Pair every limit/AOD drill with one area-of-region numerical the same day.
Step 1: write the parabola in standard form and express the geometric condition algebraically. Step 2: reduce to an equation in the unknown parameter. Step 3: extract the required integer/decimal for the NUM grid.
Conic geometry collapses into algebra; diagram alone is not enough.
Translate every parabola condition into an equation before computing.
Step 1: place the ellipse in standard form and introduce eccentric angle or slope form. Step 2: impose the geometric condition (tangent/chord/focus). Step 3: match the simplified relation to the correct option.
Parametric slips create attractive wrong options.
Keep both slope and parametric forms of ellipse tangents fluent.
Step 1: extract all shared geometric data from the paragraph once. Step 2: answer the first NUM (slope/intercept/distance). Step 3: reuse intermediates for the linked follow-ups without re-deriving from scratch.
Early example of Advanced’s linked-stem tax on organisation.
Box shared quantities at the top of linked stems — treat them as a mini formula sheet.
Why methods matter
DE full marks = classification. These methods stamp SEP/HOM/LIN before any integration — misclassification is what actually loses marks, not hard integrals.
Misclassification is the real DE killer — this stamp fixes the root cause.
Do thisOne-word stamp before any integration.
Stops mixing IF with y=vx mid-way.
dy/dx+(2/x)y=x → LIN, IF=x², not homogeneous guesswork.
Linear DE becomes one product-rule recognition, not a mystery.
Do thisWrite IF, multiply through, recognise derivative of product.
Linear DE becomes one quadrature.
d/dx(x²y)=x³ ⇒ x²y=x⁴/4+C.
Catches the algebra leak that makes y=vx solutions wrong.
Do thisWhen y=vx, differentiate with product rule: v+x v′.
Common algebra leak.
Forget product rule ⇒ wrong separable equation in v.
Keeps general solution clean so particular solution algebra does not tangle early.
Do thisFind general solution, then plug IC for C.
Keeps algebra organised.
Don’t insert IC before integrating both sides completely.
Processed examples
Read the impact line first. Then notice which family/model was chosen. The solution is written the way your rough sheet should look in the hall.
Solve dy/dx + (2/x)y = x (x>0).
Classification LIN → IF is the whole speed story.
Model chosenStamp LIN; IF=x².
Answery = x²/4 + C/x²
Takeaway: IF recipe only after LIN stamp.
Solve dy/dx = y (y>0) with y(0)=2.
Separable + IC is the cleanest DE bank question — still stamp SEP first.
Model chosenSEP: dy/y = dx.
Answery = 2eˣ
Takeaway: IC after general solution.
Solve dy/dx = (x + y)/(x − y) with y(1) = 0, giving the solution implicitly for x > 0.
Looks linear-ish but is homogeneous — misclassification is the mark killer.
Model chosenStamp HOM → y = vx → separate → apply IC.
Answertan⁻¹(y/x) − (1/2) ln(1 + y²/x²) = ln x
Takeaway: Equal-degree rational DEs → try v = y/x immediately.
Reusable models
Advanced stems cluster. Name the family in 10–15s, write the fast model, then run the same path. Do not invent a new plan each time.
Looks likedy/dx + P(x)y = Q(x)
Fast modelStamp LIN → IF=e^{∫P} → d/dx(y·IF)=Q·IF.
One recipe — no method mixing.
Do not try y=vx on a clearly linear DE.
Looks likedy/dx = f(y/x) or degree-balanced M,N
Fast modelStamp HOM → y=vx → remember product rule v+x v′.
Classification redirects you away from illegal IF.
Do not forget product rule when differentiating y=vx.
Looks likeg(y) dy = f(x) dx after rearrange
Fast modelStamp SEP → split → integrate both sides → +C → IC.
Shortest DE family when recognised early.
Do not force IF when variables already separate.
Looks likeList of DEs vs general solutions
Fast modelDifferentiate the proposed solution (or plug) independently for each list item.
Verify-by-differentiating is faster than re-solving each DE.
Do not solve all four DEs from scratch if plugging works.
Hall timing
Clear differentials into standard first-order shape.
If M(x,y)dx+N dy=0, check homogeneous degree or exactness only if in syllabus path; Advanced usually redirects to these three.
Linear: multiply by IF, left side becomes d/dx(y·IF).
Constants fixed by IC must satisfy original point.
After the model is locked
∫ dy/g(y) = ∫ f(x) dx
Variables separate cleanly
y=vx ⇒ dy/dx = v+x dv/dx = f(v)
f(y/x) form
IF=e^{∫P dx}; d/dx(y·IF)=Q·IF
dy/dx+Py=Q
Order = highest derivative order; degree = power of that derivative
Classification MC
Contains arbitrary constants equal in number to order (typical first-order → one C)
Matching solution forms
Make it automatic