Work with U and V (potential) rather than force magnitude alone; energy and Kepler’s law then decide orbital and escape stems in one ledger.
Portion MechanicsFocus Field/potential, satellites, escape and Kepler numericals with high accuracy demandTarget 60–90sPortion share 32.3%Trend Falling share
Gravitation on Advanced is inverse-square field and potential for point masses/spheres, variation of g, Kepler’s laws, satellite circular orbits, geostationary conditions and escape velocity. Prefer potential energy (−GMm/r) and mechanical energy of orbits over memorising disconnected speed formulas. Gravity template: superposition → V and g with stated zero → energy for orbits/escape. Shell/cavity = add and subtract known fields.
How Advanced asks this
g and V due to shells, spheres, or point-mass assemblies
Escape velocity from planet/surface or from a point above surface
Satellite period, altitude, energy or speed; compare orbits
Kepler law ratios for planets or binary (reduced mass awareness when needed)
Geostationary height/conditions; weightlessness in orbit
Potential energy graphs; work to move mass in gravitational field
Traps that leak marks
Using g=GM/r² inside a uniform sphere
Taking geostationary as any satellite with T=24 h regardless of inclination/orbit shape
Thinking gravity is zero in orbit because astronauts float
Using v_e=√(2gR) with g and R from different planets mixed
Forgetting factor 1/2 in circular-orbit total energy
Adding potentials as vectors
Applying Kepler T²∝a³ with wrong central mass in a binary without reduced mass when required
Using surface escape speed from an orbit without adjusting U
Setting K=|U| for circular orbits (actually K=|U|/2)
Applying exterior GM/r² inside a thick spherical shell casually
01. g⃗ = −GM r̂ /r² outside a spherical mass (or at surface with R). Inside a uniform sphere, g∝r. Potential V=−GM/r (V∞=0); U=mV.
02. Escape from surface: ½mv_e² − GMm/R = 0 ⇒ v_e=√(2GM/R)=√(2gR) if g=GM/R².
03. Circular orbit: centripetal = gravity ⇒ v=√(GM/r); T²=(4π²/GM)r³ (Kepler III for Sun-centred or Earth satellites with M≫m).
04. Geostationary: equatorial, same sense as Earth rotation, T=24 h sidereal day matching, fixed r from Kepler III. Binding energy for circular orbit is GMm/(2r).
05. Field and potential are different objects: g = −∇V (or −dV/dr radially). Superposition holds for both; energy of a mass m in a field is mV with your zero of V stated (usually ∞).
06. Orbital mechanics: centripetal demand v²/r = GM/r² for circular orbits; total E=−GMm/(2r). Escape needs E≥0 from the surface or from the orbit you start in—state the starting PE carefully.
07. Shell theorems: outside a uniform sphere acts as point mass; inside a shell field is zero. Density and cavity problems are superposition, not new constants.
Official · 2026
Syllabus for this topic
Official syllabus points for Gravitation only — not the full Mechanics portion map. Portion hub: Mechanics · Mechanics analysis.
Syllabus on this page is topic-scoped: Gravitation. The parent portion (Mechanics) also covers other topics — use the portion hub for the full map.
Must cover (this topic)
Gravitation: satellites, escape, Kepler
Gaps / watch-outs
No topic-specific exclusions flagged — finish the unit points below for Gravitation.
Advanced rarely asks a chapter in isolation. These are tagged multi-idea Physics stems that touch Gravitation — practise the knowledge bridge, not only the single-chapter drill.
Physics2026 · Paper 1 · Q1single-correct
Rolling disks + relative rotation on a large disk
Mechanics – Rotation+Rolling without slipping+Relative angular motion
Knowledge bridge
Step 1: relate arc lengths so the small disks roll without slipping on the large circumference (geometry of contact). Step 2: convert path radius R+r into orbital and spin rates (ω/51-type ratios). Step 3: close the remaining angular gap 2π − Δθ to get the meeting time τ.
Why it feels hard
Easy to use the wrong Δθ (2/51 vs 4/51) if relative rolling sense is mishandled.
What to practise
Always draw contact velocities and write v = ωr for every rolling interface before algebra.
Region-wise field/potential and circular-orbit energy relations organise almost every gravity stem.
01
Potential superposition
Potential is easier than vector g for assemblies and energy questions.
Do thisAdd scalar V from each spherical/point piece; then g=−∇V or use symmetry for g.
Why it works
Potential is easier than vector g for assemblies and energy questions.
See it once
Two masses: V at a point is −GM₁/r₁−GM₂/r₂; equipotential ≠ equal field.
02
Energy to infinity
One criterion covers surface escape, escape from orbit, and ‘minimum energy to remove’.
Do thisEscape and binding questions: require E≥0 at infinity relative to V∞=0.
Why it works
One criterion covers surface escape, escape from orbit, and ‘minimum energy to remove’.
See it once
From circular orbit, need ΔE = +GMm/(2r) to reach E=0.
03
Kepler ratio cancel GM
Avoids inserting G and M when only ratios are asked.
Do thisFor two orbits about same centre, (T₁/T₂)²=(a₁/a₂)³.
Why it works
Avoids inserting G and M when only ratios are asked.
See it once
If a doubles, T grows by 2√2.
04
Shell theorem gate
Prevents using GM/r² inside cavities or thick shells wrongly.
Do thisOutside: as point mass at centre; inside a thin shell: g=0, V=constant=−GM/R.
Why it works
Prevents using GM/r² inside cavities or thick shells wrongly.
See it once
Uniform sphere cavity problems: superposition of full sphere minus imaginary sphere.
Processed examples
Sample questions · full working
Read the impact line first. Then notice which family/model was chosen. The solution is written the way your rough sheet should look in the hall.
01
bankFamily · Orbital mechanics / Kepler
Sample question
Find orbital speed for a circular orbit of radius 2R about Earth. Take g at surface and R known: express in √(gR).
This stem rewards early recognition of the orbital mechanics / kepler model.
Model chosenGM=gR²; v=√(GM/r).
Processed solution
v=√(gR²/(2R))=√(gR/2).
Answer√(gR/2)
Takeaway: Replace GM using surface g.
02
standardFamily · Field and potential of spherical mass
Sample question
Potential at the surface of a uniform sphere is −V₀. Find potential at the centre.
This stem rewards early recognition of the field and potential of spherical mass model.
Model chosenInside uniform sphere V(r)=−(GM/(2R))(3−r²/R²).
Processed solution
At centre, V=−(3/2)GM/R.
Surface V=−GM/R=−V₀.
Centre potential=−(3/2)V₀.
Answer−(3/2)V₀
Takeaway: Potential is continuous and deepest at the centre.
03
twistFamily · Satellite transfer and energy change
Sample question
A satellite in circular orbit of radius 2R (planet radius R) is to be transferred to a circular orbit of radius 8R via a Hohmann ellipse. Find the total Δv required in terms of g and R (g=GM/R²).
This Advanced-level variation couples hidden constraints with the satellite transfer and energy change model.
Model chosenHohmann: two burns at periapsis and apoapsis using vis-viva.
Vis-viva at periapsis: v_p=√[GM(2/2R−1/5R)]=√(gR·0.8).
At apoapsis: v_a=√[GM(2/8R−1/5R)]=√(gR·0.05).
Δv=(v_p−v₂)+(v₈−v_a).
AnswerΔv=√(gR)[√0.8−√(1/2)+√(1/8)−√0.05]
Takeaway: Transfer costs are differences between circular and elliptical speeds at the same r.
Reusable models
Common question families
Advanced stems cluster. Name the family in 10–15s, write the fast model, then run the same path. Do not invent a new plan each time.
01
Field and potential of spherical mass
Looks likePoint outside/inside uniform sphere or shell
Fast modelOutside: like point mass; inside shell E=0; inside solid E∝r.
Same solve path
Classify region (r≷R).
Write E(r) and V(r) for that region.
Use superposition for cavities/shells.
Relate g = −dV/dr.
Rough skeleton
region
E,V
superpose
Why faster
Recognition fixes the model before arithmetic begins.
Refuse this
Do not start blind expansion or casework before identifying the governing model.
02
Orbital mechanics / Kepler
Looks likeCircular orbit, period, energy, or escape
Fast modelUse GMm/r² = mv²/r and E=−GMm/(2r) for circular.
Same solve path
Write force balance or energy.
Insert Kepler T²∝a³ if needed.
Compute v, T, or E.
Compare escape v_esc=√(2GM/r).
Rough skeleton
balance/energy
orbit params
result
Why faster
Recognition fixes the model before arithmetic begins.
Refuse this
Do not start blind expansion or casework before identifying the governing model.
03
Satellite transfer and energy change
Looks likeRaise orbit, geostationary, or binding energy
Fast modelΔE from E=−GMm/(2a) between orbits.
Same solve path
Find initial and final semi-major axes.
Compute E_i and E_f.
ΔE = E_f − E_i is the fuel/work bookkeeping.
Check circular vs elliptical wording.
Rough skeleton
a_i, a_f
E
ΔE
Why faster
Recognition fixes the model before arithmetic begins.
Refuse this
Do not start blind expansion or casework before identifying the governing model.
04
Gravitational self-energy / binding
Looks likeUniform sphere self-energy or dismantling work
Fast modelU_self = −(3/5)GM²/R for uniform sphere (standard result).
Same solve path
Identify mass distribution.
Apply known self-energy or integrate shells.
Relate to escape/binding if asked.
Watch sign (bound ⇒ negative).
Rough skeleton
distribution
U_self
sign
Why faster
Recognition fixes the model before arithmetic begins.
Refuse this
Do not start blind expansion or casework before identifying the governing model.
Hall timing
60–90s process
0–15s
Field/potential superposition vs satellite energy vs escape vs Kepler ratio.
Underline given data, unknowns and constraints. Name the mechanical model before recalling any formula; discard relations whose assumptions are already broken.
15–35s
Write V or U with V∞=0; for orbits write E=K+U and centripetal balance.
Draw axes, free-body or energy/impulse diagram. Write governing equations symbolically with consistent sign and reference.
35–75s
Solve for r,v,T or ΔE; use T²∝r³ ratios when possible.
Solve algebraically as far as possible; substitute numbers only once. Keep vectors, components and units on the rough sheet.
75–90s
Check inside/outside sphere formula choice, and geostationary constraints if claimed.
Check dimensions, limiting cases and physical sense. For multi-correct, test every option independently rather than forcing one narrative.
After the model is locked
Quick formula bank
Field (point/sphere outside)
g = GM/r² toward centre
r≥R spherical mass
Potential
V = −GM/r (V_∞=0); U = −GMm/r
Point mass / outside sphere
Escape speed
v_e = √(2GM/r) from distance r
Reach infinity with E≥0
Circular orbit
v_c = √(GM/r); T = 2π√(r³/GM)
Satellite, M≫m
Orbit energy
E = −GMm/(2r) circular; E=−GMm/(2a) ellipse
Total mechanical energy
Kepler III
T² ∝ a³ / M_central (fixed central mass)
Period–orbit size ratios
g variation
g′ ≈ g(1−2h/R) for h≪R above surface; inside uniform: g(r)=GMr/R³
Near-Earth or interior
Geostationary r
T=2π√(r³/GM_E)=1 sidereal day
Geo orbit radius
Mental bank
V_∞=0; V=−GM/r outside
v_e=√(2GM/r); v_c=√(GM/r); v_e=√2 v_c
Circular E=−GMm/(2r)
T² ∝ r³ (same M)
Inside uniform sphere g∝r
Thin shell: g=0 inside; V=−GM/R inside
Geostationary: equatorial, T≈24 h, correct r and sense
Weightlessness in orbit: continuous free fall, g≠0
V(∞)=0 ⇒ V=−GM/r outside a point/sphere
Circular: E=K+U=−GMm/(2r)
Escape: ½mv_esc² = −U_start (to reach E=0)
Inside uniform shell: g=0; cavity = full − removed
Make it automatic
Practice · checklist
Daily
Two potential/field superposition or shell-theorem drills.
One satellite energy/period and one escape-speed numerical.
Weekly
One mixed Kepler + geostationary + orbit-raise set.
Derive v_e and E_circular from energy+force balance without notes.
100% checklist
Inside vs outside formula chosen correctly
Potential scalar superposition used when appropriate
V∞=0 energy zero point consistent
Circular orbit: force balance and E=−GMm/(2r)
Kepler ratios only for same central mass (or corrected)
Escape criterion E≥0 applied at correct r
Geostationary conditions all checked if claimed
Zero of potential stated
Field vs potential distinguished in the ask
Orbit/escape energy bookkeeping from the correct radius