Electrostatics: Field & Potential
PromiseSeparate field (vector, force) from potential (scalar, energy), then use superposition and ΔV = −∫E·dl instead of memorising isolated formulas.
01. Coulomb’s law gives force between point charges in vacuum; field of a charge is force per unit test charge, always directed by the source-charge sign.
02. Potential is a scalar superposition: V = Σkqi/ri (zero at infinity for finite charge sets). Field follows from E = −dV/ds along a path of steepest decrease.
03. A dipole in a uniform field feels τ = p × E and U = −p·E; net force is zero only when E is uniform.
How Advanced asks this
- Net E or V at a point from a charge configuration
- Work to assemble charges or move a charge in a field
- Dipole torque/PE/equilibrium in uniform E
- Field-line or equipotential statement audits
- Relation between E and ΔV for planar or radial geometries
Traps that leak marks
- Adding |E| instead of components
- Using U=−pE cosθ in a strongly nonuniform field for force claims
- Setting V=0 at a conductor surface without stating the gauge
- Confusing field-line density with charge density alone
- Forgetting PE of a system includes all interaction pairs
- Treating V as a vector or averaging E blindly for ΔV
- Using point-charge E inside a conductor’s material
- Forgetting induced charges on grounded conductors
Must cover (this topic)
- Dipole PE in uniform field
60–90s process
- 0–15s — Classify: point-charge superposition, continuous-charge estimate, dipole-in-uniform-E, or E↔V conversion.
- 15–35s — Fix origin/reference (usually V∞=0). Write vector E components or scalar V sum before combining.
- 35–75s — Superpose; convert to force/energy/torque only after E or V is clear. Keep k=1/(4πε₀) symbolic until the last step.
- 75–90s — Check units (N/C or V/m), sign of work qΔV, and whether uniform-field dipole formulas were misused for nonuniform E.
Methods that change the score
Vector E versus scalar V superposition is the electrostatics operating system.
Method 01 · Component superposition
E is a vector; magnitude-only addition invents false cancellations.
Do this: Resolve each E into axes; never add magnitudes unless collinear and same sense.
Method 02 · Potential-first energy
Scalar V is cheaper than integrating vector force along a path when electrostatic.
Do this: Compute V at the location, then U = qV or W = qΔV.
Method 03 · Dipole angle map
One angle convention prevents torque/PE sign flips.
Do this: Measure θ from p to E; stable equilibrium at θ=0, unstable at θ=π.
Method 04 · Field-line audit
Kills distractors without calculation.
Do this: Test statements with: lines leave +, never cross, density ∝ |E|, closed loops forbidden in electrostatics.
Quick formulas
- Coulomb force: F = k |q₁q₂|/r² r̂; k = 1/(4πε₀) — Two point charges in vacuum
- Point-charge field: E = k q/r² r̂ (away if q>0) — Field of a point source
- Potential: V = k q/r (V∞=0); V = Σ k qi/ri — Scalar potential of point charges
- E–V link: ΔV = −∫ E·dl; E = −dV/ds along field — Uniform or known-E paths; electrostatics
- Uniform-field PE: U = q V; ΔU = q ΔV — Charge moved between equipotentials
- Dipole moment: p = q × 2a ( − to + ) — Two equal opposite charges
- Dipole in uniform E: τ = p E sinθ; U = −p E cosθ — Uniform external field only
- Work by external agent (slow): W_ext = ΔU (no KE change) — Quasi-static assembly/move
Common question families
Point-charge field and potential
Looks like: Superposition of E and V for discrete charges
Fast model: E is vector sum; V is scalar sum (choose reference).
Electric dipole
Looks like: Field on axis/equator; torque/energy in uniform E
Fast model: p = qd; τ=p×E; U=−p·E in uniform field.
Potential from field / equipotentials
Looks like: V = −∫E·dl; E=−∇V
Fast model: Integrate along a convenient path; use equipotential shortcuts.
Conductor electrostatics
Looks like: Charge on surface, E=0 inside, V constant
Fast model: Excess charge resides on outer surface of conductor; cavity rules apply.
Sample preview · Point-charge field and potential
Two charges +q and +q are separated by 2a. Find potential at the midpoint (reference at infinity).
Answer: 2kq/a
Potentials add as scalars.
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